Sebuah keping besi tebal 2 cm dengan luas penampang 5000 cm², sisi yang satu bersuhu 150 C dan yang lain 140 C. Berapa kalor berpindah melalui keping setiap detik ? k(besi)=80W/m.K
Sat Mar 14, 2009 11:59 pm
ati9200
Joined: Wed Nov 05, 2008 3:55 pm Posts: 19
Re: soal,,tlong bntuan nya..
Hmmm.....
kyanya gw tau ddeh cara ngerjainnya....pake Newton cooling law
\frac{Q}{t}=kA\frac{T_2-T_1}{x_2-x_1}
jadi
\frac{Q}{t}=80 0.5 (150-140)/0.02=40000 J/s
kayanya gitu sih...menurut lo bener ga
Sun Mar 15, 2009 7:50 pm
admin
Admin
Joined: Tue Nov 04, 2008 3:06 pm Posts: 112
Re: soal,,tlong bntuan nya..
@ati9200
good work.....
keep a good work...nanti sy jadiin moderator loh kalo sering jawabin soal
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